Решить логарифмическое неравенство
X>0 log(1/5)x=a 4a²-11a+7≤0 D=121-112=9 a1=(11-3)/8=1 a2=(11+3)/8=7/4 1≤a≤7/4 log(1/5)x≥1⇒x≤1/5 log(1/5)x≤7/4⇒x≥1/ x∈[]
![5 \sqrt[4]{125}](https://tex.z-dn.net/?f=5+%5Csqrt%5B4%5D%7B125%7D+ "5 \sqrt[4]{125}")
![1/5 \sqrt[4]{125} ;1/5](https://tex.z-dn.net/?f=1%2F5+%5Csqrt%5B4%5D%7B125%7D+%3B1%2F5 "1/5 \sqrt[4]{125} ;1/5")
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