Решите систему неравенств. 2,4 ПОЖАЛУЙСТА!!!

$\left \{ {{x - \frac{x+3}{2} \geq 1,3 } \atop {- \frac{x}{2} \leq 2- \frac{x}{3} }} \right. \\ \left \{ {{2x-(x+3)} \geq 2,6 \atop {-3x \leq 12 - 2x}} \right. \\ \left \{ {{2x-x-3 \geq 2,6} \atop {-3x+2x \leq 12}} \right. \\ \left \{ {{x \geq 5,6} \atop {x \geq -12}} \right. \\$
Ответ: [5,6; +∞ ) или $x \geq 5,6$

$\left \{ {{ \frac{x}{5} - \frac{2}{3} \ \textless \ \frac{2}{5} - \frac{x}{3} } \atop { \frac{2}{7} + \frac{x}{3} \ \textgreater \ \frac{x}{7} - \frac{2}{3} }} \right. \\ \left \{ {{3x-10\ \textless \ 6-5x} \atop {6+7x\ \textgreater \ 3x-14}} \right. \\ \left \{ {{8x\ \textless \ 16} \atop {4x\ \textgreater \ -20}} \right. \\ \left \{ {{x\ \textless \ 2} \atop {x\ \textgreater \ -5}} \right.$
Ответ: $(-5;2)$ или $-5 \ \textless \ x \ \textless \ 2$