2(х + 4)^4 - 3(х + 4)^2 =0

Question

2(х + 4)^4 - 3(х + 4)^2 =0

Answer 1

(х+4)^2 ( 2(х+4)^2 - 3) = 0
1)  (х+4)^2 = 0 
x = -4
2)  2(х+4)^2 - 3 = 0
(х+4)^2 = 1.5
x^2+8x+16-1.5 = 0
x^2+8x + 14.5 = 0
D = 64 - 58 = 6
x = (-8 +-корень 6) \ 2