Неравенство, 9 класс!!!!!!!!!!!!

$4x^{2} + 4x +2( \sqrt{2x+1}) ^{2} \leq 34 \\$

ОДЗ:   2x+1 ≥ 0
  2x ≥ -1
x ≥ -1/2

$4x^{2} + 4x +2*(2x+1) \leq 34 \\ 4x^{2} + 4x +4x+2 \leq 34 \\ 4x^{2} + 8x - 32 \leq 0 | :4\\ x^{2} + 2x - 8 \leq 0 \\$
$(x-2)(x+4) \leq 0 \\$

+ -4 - 1/2 2 +
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Ответ: [ - 1/2 ; 2 ] .