Найдите множество корней в уравнении. (6-3х)^2=4х-8
(6-3x)² = 4x-8 36 - 36x + 9x² - 4x + 8 = 0 9x² - 40x + 44 = 0 a=9, b = -40, c = 44 D/4 = (b/2)² - ac D/4 = 400-396 = 4, √D/4 = 2 x = (-b/2 +-√D/4)/a x1 = (20+2)/9 = 22/9 = 2 и 4/9 x2 = (20-2)/9 = 18/9 = 2 Ответ: 2 и 4/9, 2