(3x + 1/3) в квадрате=....? (ab-cx)(ab+cx)=....? (0.4a-10c)(o.4a+10c)=....? (ax-3) в...

Question

(3x + 1/3) в квадрате=....?

(ab-cx)(ab+cx)=....?

(0.4a-10c)(o.4a+10c)=....?

(ax-3) в квадрате=.....?

Answer 1

(3x + 1/3) в квадрате=9x2+2x+1/9

(ab-cx)(ab+cx)=ab2-cx2

(0.4a-10c)(o.4a+10c)=0,16a2-100c2

(ax-3) в квадрате=ax2-6ax+9