Дана функция f(x)=6ln(1/3*x).Найдите f'(x);f'(1/3) HELP PLZ
ln ( ?)
1/3x ili x/3 ?
одна третья икса
Takže x/3.......
Да
Ln (x/3) = ln x - ln3, derivacie(proizvodnaja)=1/x f´(x) = 6. 1: (x/3) .1/3 = 6.1/x=6/x f´(1/3) = 6/(1/3) = 6.3 = 18