Помогите решить пожалуйста! номер 129
Решение 1) sin(π/6) + cos(π/3) + tg(π/4) - ctg(π/4) = 1/2 + 1/2 + 1 - 1 = 1 2) sin(-π/2)*cos(-π/2)*tg(-π/4)*ctg(-π/2) = - 1*0*(-1)*0 = 0 3) sin²(π/6) - cos²(π/4) + tg³(π/4) - ctg²(-π/4) = = (1/2)² - (1/√2)² + 1³ - (-1)² = 1/4 - 1/2 + 1 - 1 = - 1/4
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