(x+1)^2 >x(x+2) a^2+ 1 >2(3а-4)

Question

(x+1)^2 >x(x+2)
a^2+ 1 >2(3а-4)

Answer 1

X^2+1x+1^2>x^2+2x
x^2+1x+1-x^2-2x>0
x>1
a^2+1>6a-8
a^2+1-6a+8>0
a^2-6a+9>0
D=6^2-4*1*9=0