F(x)=(15-2x-x^2)•(2x+2/x-1/x^2)

Решите задачу:

$F(x)=(15-2x- x^{2} )(2x+ \frac{2}{x} - \frac{1}{ x^{2} } ) \\ F'(x)=(-2-2x)(2x+ \frac{2}{x} - \frac{1}{ x^{2} } )+(15-2x- x^{2} )(2- \frac{2}{ x^{2} }+ \frac{2}{ x^{3} } )=$ $-4x- \frac{4}{x} + \frac{2}{ x^{2} } -4 x^{2} -4 + \frac{2}{ x } +30- \frac{30}{ x^{2} } + \frac{30}{ x^{3} } -4x+ \frac{4}{ x } - \frac{4}{ x^{2} }-2 x^{2} +2-$ $\frac{2}{x} =$ $\frac{30}{ x^{3} }-\frac{32}{ x^{2} } -6 x^{2}-8x +28$