Первую цепочку. и вторую.
1. 1.CH4+Cl2=CH3Cl+HCl 2. CH3Cl+NaOH=CH3OH+NaCl 3. CH3OH+CuO=HCOH 4.HCOH+H2=CH3OH 5.HCOH+[O]=HCOOH 2. 1. 2CH4=C2H2+3H2 2.C2H2+[O]=CH3COH 3. CH3COH+Ag2O=CH3COOH+2Ag 4.CH3COH+H2=C2H5OH 5.C2H5OH+3O2=2CO2+3H2O
что значит [о]?