Решите уравнение,нужно очень плиз log5(x+1)+logg5(x-3)=1

Решите задачу:

$\log_5(x+1)+\log_5(x-3)=1\\ \left \{ {{\log_5((x+1)(x-3))=1} \atop { \left \{ {{x+1\ \textgreater \ 0} \atop {x-3\ \textgreater \ 0}} \right. }} \right. \\ \left \{ {{x^2-2x-3=5} \atop { \left \{ {{x\ \textgreater \ -1} \atop {x\ \textgreater \ 3}} \right. }} \right. \\ \left \{ {{x^2-2x-8=0} \atop {x\ \textgreater \ 3}} \right\\ \left \{ {{[{x=-2\atop x=4}} \atop {x\ \textgreater \ 3}} \right. \\x=4$