(х-1)^2=2х^2-6х-31 помогите решить
X^2 - 2x + 1 = 2x^2 - 6x - 31 x^2 - 2x + 1 - 2x^2 + 6x + 31 = 0 - x^2 + 4x + 32 = 0 x^2 - 4x - 32 = 0 D = 16 + 4*32 = 144 x1 = (4 + 12)/2 = 8; x2 = ( 4 - 12)/2 = - 4
(x-1)^2=2х^2-6х-31 x^2-2x+1=2x^2-6x-31 -x^2+4x+32=0 делим на -1 x^2-4x-32=0 D= 16- 4*(-32) D=144=12^2 x1=(4+12)/2=8 x2=(4-12)/2=-4 Ответ: 8;-4