2) {3y-x+24=27 ; {3y-x=3
{log(2) ((2x-2y)/(5-y^2))=1; {log(2) ((2x-2y)/(5-y^2))=log(2) 2
{x=3y-3
{2x-2y)/(5-y^2)=2 (6y-6-2y) / (5-y^2)=2; (4y-6) /(5-y^2)=2
5-y^2≠0; 4y-6-10+2y^2=0; 2y^2+4y-16=0; y^2+2y-8=0;
D=1+8=9=3^2;
y1=-1-3=-4; y2=-1+3=2
y=-4; x=3*(-4)-3=-15
y=2; x=3*2-3=3
Ответ. (-15;-4) (3;2)