Решите плиз! алгебра, ,,,,,,,,,,,,,,,,,,

Решите задачу:

$(2+ \frac{1}{3+ \frac{3}{4}})-(1+ \frac{1}{1+ \frac{2}{3}})=(2+ \frac{1}{ \frac{15}{4}})-(1+ \frac{1}{\frac{5}{3}})=(2+ \frac{4}{15})-(1+ \frac{3}{5})=\\\\ ( \frac{30+4}{15})- (\frac{5+3}{5})= \frac{34}{15}- \frac{8}{5}= \frac{34-24}{15}= \frac{10}{15}= \frac{2}{3}$

$4- \frac{1}{3- \frac{1}{2- \frac{1}{2}}}=4- \frac{1}{3- \frac{1}{ \frac{3}{2}}}=4- \frac{1}{3- \frac{2}{3}}=4- \frac{1}{ \frac{7}{3}}=4- \frac{3}{7}= \frac{28-3}{7}= \frac{25}{7}=3 \frac{4}{7}$

$36=36:2=18:2=9:3=3:3=1 \Rightarrow 36=2\cdot2\cdot3\cdot3$