Решите уравнение: (x-5)^2+2(x-5)-63=0
(х^2-2*5х+25)+2х-2*5-63=0
х^2-10х+25+2х-10-63=0
х^2-8х-48=0
Д=b^2-4ac=8^2-4*1*(-48)=64+192=256=16^2
x1=(8+16)/2=12
х2=(8-16)/2=-4
x^2-10x+25+2x-10-63=0
x^2-8x-48=0
D=64+192=256
x=(8-+16)/2
x1=-4 x2= 12