Решение
log₀,₅ [(3x - 2)/(x + 2)] > 1
log₀,₅ [(3x - 2)/(x + 2)] > log₀,₅ (0,5)
так как 0
< 0,5 < 1, то
(3x - 2)/(x + 2) < 0,5
(3x - 2) - 0,5*(x + 2)]/(x + 2) < 0
(3x – 2 – 0,5x – 1)*(x + 2) < 0
(2,5x – 3)*(x + 2) < 0
(2,5x – 3)*(x + 2) = 0
2,5x – 3 = 0, x = 1,2
x + 2 = 0, x = - 2
x ∈ (- 2; 1,2)