Решить систему уравнений x^2-y=28 x-y=2

Question

Решить систему уравнений x^2-y=28
x-y=2

Answer 1

Y=x-2
x²-x+2=28
x²-x-26=0
D=1+676=677
x1=(1-√677)/2⇒y1=(1-√677)/2-2=(-3-√677)/2
x2=(1+√677)/2⇒y2=(-3+√677)/2

Comments

где взяли 28?

Answer 2

 x-2y=-28;x-y=-2 

Solution :

 {x,y} = {24,26} 

System of Linear Equations entered :

  [1] x - 2y = -28   [2] x - y = -2

Graphic Representation of the Equations :

-2y + x = -28 y + x = -2
olve by Substitution :

// Solve equation [2] for the variable  x  
 

[2] x = y - 2

// Plug this in for variable  x  in equation [1]

  [1] (y -2) - 2y = -28   [1] - y = -26

// Solve equation [1] for the variable  y  

  [1] y = 26 

// By now we know this much :

  x = y-2   y = 26

// Use the  y  value to solve for  x  

  x = (26)-2 = 24 

Solution :

 {x,y} = {24,26}