24-(3y-1)(4y-5)=(11-6y)(2y-7)=?

Question

24-(3y-1)(4y-5)=(11-6y)(2y-7)=?

Answer 1

24=(3у-1)(4у-5)+(11-6у)(2у-7)
24=(12у²-15у-4у+5)+(22у-77-12у²+42у)
24=12у²-19у+5+64у-77-12у²
24=45у-72 (: 3)
 8=15у-24
15у=32     
  у=32/15
 у=2целых  2/15
 у=2,133(3)