24-(3y-1)(4y-5)=(11-6y)(2y-7)=?
24=(3у-1)(4у-5)+(11-6у)(2у-7) 24=(12у²-15у-4у+5)+(22у-77-12у²+42у) 24=12у²-19у+5+64у-77-12у² 24=45у-72 (: 3) 8=15у-24 15у=32 у=32/15 у=2целых 2/15 у=2,133(3)