1→ (01.2012 до 01.2013): a+a*p/100 =a(1+p/100)
* * * исходная сумма умноженное на коэффициент k =1+p/100 .* * *
2 → (01.2013 до 01.2014): a(1+p/100)*(1+p/100)=a(1+p/100)² ;
[ a(1+p/100) + a(1+p/100) *p/100 =a(1+p/100)*(1+p/100)=a(1+p/100)²]
3 → (01.2014 до 01.2015): a(1+p/100)³ ;
4 → (01.2015 до 01.2016): a(1+p/100)⁴ ;
5 → (01.2016 до 01.2017): a(1+p/100)⁵ . p = 7
a(1+7/100)⁵ =a*(1,07)⁵
---
a*(1,07)^n > 2a ⇔ (1,07)^n >2 ⇒n >Lg2/Lg1,07 ≈10