ОЧЕНЬ СРОЧНО !!!! ПОМОГИТЕ!!!! {4x+3y=6 {2x+8y=1

$\left \{ {{4x+3y=6} \atop {2x+8y=1}} \right.$

$\left \{ {{4x+3y=6} \atop {-4x-16y=-2}} \right.$

$\left \{ {{-13y=4} \atop {4x+3y=6}} \right.$

$\left \{ {{y=- \frac{4}{13} } \atop {4x+3*(- \frac{4}{13}) =6}} \right.$

$\left \{ {{y=- \frac{4}{13} } \atop {4x- \frac{12}{13} =6}} \right.$

$\left \{ {{y=- \frac{4}{13} } \atop {4x=6\frac{12}{13} }} \right.$

$\left \{ {{y=- \frac{4}{13} } \atop {4x=\frac{90}{13} }} \right.$

$\left \{ {{y=- \frac{4}{13} } \atop {x=1\frac{19}{26} }} \right.$

Ответ: $(1 \frac{19}{26};- \frac{4}{13})$