(10y+1)⋅(2y−4)=(20y−5)(y+1) Решите уравнение!!!!

Question

(10y+1)⋅(2y−4)=(20y−5)(y+1) Решите уравнение!!!!

Answer 1

20y2-40y+2y-4=20y2+20y-5y-5
20y2-40y+2y-4-20y2-20y+5y+5=0
-53y+1=0
-53y=-1
53y=1
y=1/53