1-sin x =sin ^2 (П/4-x/2)

Question

1-sin x =sin ^2 (П/4-x/2)

Answer 1

sin x =cos ^2(П/4-x/2)=(cosП/4cosx/2+sinП/4sinx/2)^2=(1+sinx)/2

sinx=1

x=П/2 +2Пn