5а(6-3а)+6а= (х+3у)-(2х-5у)+(у-1)=

Question

5а(6-3а)+6а=
(х+3у)-(2х-5у)+(у-1)=

Answer 1

5a(6-3a)+6a=30a-15a^2+6a=36a-15a^2
(x+3y)-(2x-5y)+(y-1)=x+3y-2x+5y+y-1=-x+9y-1