Решить уравнение относительно Х: 1) x^2-5ах-6а^2=0 2)х^2 -7ах+10а^2=0

1.) $x^{2}-5ax-6a^{2}=0 | : x^{2}\\ 5\frac{a}{x}-6\frac{a^{2}}{x^{2}} = 0\\ 6\frac{a^{2}}{x^{2}}-5\frac{a}{x} = 0\\\\ \frac{a}{x}=t\\\\ 6t^{2}-5t=0\\ t(6t-5)=0\\ t=0; \ 6t-5=0;\ 6t=5;\ t=\frac{5}{6};$

2.) $x^{2}-7ax+10a^{2}=0 | : x^{2}\\ -7\frac{a}{x}+10\frac{a^{2}}{x^{2}} = 0\\ 10\frac{a^{2}}{x^{2}}-7\frac{a}{x} = 0\\\\ \frac{a}{x}=t\\\\ 10t^{2}-7t=0\\ t(10t-7)=0\\ t=0; \ 10t-7=0;\ 10t=7;\ t=\frac{7}{10}=0,7;$