Arcsin√3\2 - arccos1 + arctg(-√ 3):arctg(- √3\3)=

Question

Arcsin√3\2 - arccos1 + arctg(-√ 3):arctg(- √3\3)=

Answer 1

= arcsin√3/2 - arccos1 + (arctg√3)/(arctg√3/3)= π/3-0+ π/3:π/6=π/3+2