Решите уравнение б)4y^3-y=0 в)x^4-x^2=0 г)9y^2-4y^4=0

Question

Решите уравнение б)4y^3-y=0 в)x^4-x^2=0 г)9y^2-4y^4=0

Answer 1

4y^3 - y =0
y(4y^2 - 1) = 0
y =0
4y^2 - 1 = 0
4y^2 = 1
y^2 = 1/4
y = 1/2
y = - 1/2
Ответ: y1 = 0, y2 = 1/2, y3 = - 1/2.

x^4 - x^2 = 0
x^2(x^2 - 1)=0
x^2 = 0
x = 0
x^2 - 1 = 0
x^2 = 1
x = 1
x = - 1
Ответ: x1 = 0, x2 = 1, x3 = - 1

9y^2 - 4y^4 = 0
y^2( 9 - 4y^2) = 0
y^2 = 0
y = 0
9 - 4y^2 = 0
- 4y^2 = - 9
4y^2 = 9
y^2 = 9/4
y = 3/2
y =- 3/2
Ответ: y 1 = 0, y2 = 3/2, y3 = - 3/2.

Comments

пожалуйста,успехов!)))