Помогите пожалуйста c 587

$\left\{\begin{matrix} \frac{2x}{3} &= &\frac{3y}{4} &- &2 \\\\ \frac{1}{2}x &+ &\frac{1}{4}y &= &5 \end{matrix}\right.\\\\\\ \left\{\begin{matrix} \frac{2x}{3} &- &\frac{3y}{4} &= &-2 \\\\ \frac{1}{2}x &+ &\frac{1}{4}y &= &5 \ |(\cdot3) \end{matrix}\right.\\\\\\ \left\{\begin{matrix} \frac{2x}{3} &- &\frac{3y}{4} &= &-2 \\\\ \frac{3x}{2} &+ &\frac{3y}{4} &= &15 \end{matrix}\right.\\\\\\ \frac{2x}{3}+\frac{3x}{2}=13\\\\ \frac{4x+9x}{6}=13 \ \ |(\cdot\frac{1}{13})\\\\ \frac{x}{6}=1\\\\ x=6$

Ответ: $x=6; \ y=8$

$\left\{\begin{matrix} \frac{3}{7}x &- &\frac{2}{5}y &= &2 \\\\ \frac{3}{4}x &+ &\frac{1}{6}y &= &12\frac{1}{6} \ |(\cdot \frac{4}{7}) \end{matrix}\right.\\\\\\ \left\{\begin{matrix} \frac{3}{7}x &- &\frac{2}{5}y &= &2 \\\\ \frac{3}{7}x &+ &\frac{4}{42}y &= &\frac{146}{21} \end{matrix}\right.\\\\\\ -\frac{2}{5}y-\frac{4}{42}y=2-\frac{146}{21}\\\\ -\frac{104}{210}y=-\frac{104}{21}\\\\ y=10\\\\\\ \frac{3}{7}x-\frac{2}{5}\cdot10=2\\\\ \frac{3}{7}x=2+4\\\\ 3x=42\\\\ x=14$

Ответ: $x=14;\ y=10$