(х+3)^2 + ( х - 7)^2= 2х^2

Question

(х+3)^2 + ( х - 7)^2= 2х^2

Answer 1

1) (х+3)(х+3)= х^2+3x+3x+9=x^2+6x+9
2) (x-7)(x-7)=x^2-7x-7x+49=x^2-14x+49
3) x^2+6x+9+x^2-14x+49=2x^2
    2x^2-8x+58=2x^2
     2x^2-8x-2x^2=-58
    -8x=58
     x=-58/-8
     x=7,25