(x+3)²-x²=33 x²-(x-5)²=10 (x+12)²=x(x+8) (x-3)(x+1)=(x-2)²

Question

(x+3)²-x²=33
x²-(x-5)²=10
(x+12)²=x(x+8)
(x-3)(x+1)=(x-2)²

Answer 1

1) (х+3)2-х2=33
х2+6х+9-х2=33
6х=24
х=4
2)х2-(х-5)2=10
х2-х2+10х-25=10
10х=35
х=3.5
3)(х+12)2=х(х+8)
х2+24х+144=х2+8х
х2+24x+144-x2-8x
16x=-144
x=-9
4)(x-3)(x+1)=(x-2)2
x2+x-3x-3=x2-4x+4
x2+x-3x-3-x2+4x-4=0
2x=12
x=6