(x+3)^2+(2-x)(2+x)=0. пже

Question

(x+3)^2+(2-x)(2+x)=0. пже

Answer 1

X^2-2*3x+3^2+2^2-x^2=0
x^2-6x+9+4-x^2=0
x^2 сокращаются
-6x+13=0
-6x=-13
x=13/6 = 2 1/6

Answer 2

(х+3)²+(2-х)(2+х)=0
х²+6х+9+4-х²=0
6х+13=0
6х=-13
х=-13:6
х=-2 1/6
Проверка:
(-2 1/6+3)²+(2-(-2 1/6))(2+(-2 1/6)=0
(-2 1/6+2 6/6)²+(2+2 1/6)(2-2 1/6)=0
(5/6)²+4 1/6*(-1/6)=0
5²/6²-25/6*1/6=0
25/36-25/36=0
0=0