Решите систему уравнений!

$\left \{ {{10-x+2y=18+4y} \atop {2x-3-3y=6x-2y}} \right.$

$\left \{ {{y=-4-\frac{x}{2}} \atop {2x-3-3y=6x-2y}} \right.$

$\left \{ {{y=-4-\frac{x}{2}} \atop {2x-3-3(-4-\frac{x}{2})=6x-2(-4-\frac{x}{2})}} \right.$

$\left \{ {{y=-4-\frac{x}{2}} \atop {-\frac{8x}{2}=-1}} \right.$

$\left \{ {{y=-4-\frac{x}{2}} \atop {x=\frac{1}{4}}} \right.$

$\left \{ {{y=-4.125 \atop {x=\frac{1}{4}}} \right.$

Ответ: $x=\frac{1}{4}}$ ; $y=-4.125$ ;