(5х+3)(4-х)=х²-7 к виду ax²+bx+c=0

Question

(5х+3)(4-х)=х²-7 к виду ax²+bx+c=0

Answer 1

(5x+3)(4-x)=x^2-7
20x-5x^2+12-3x-x^2+7=0
-6x^2+17x+19=0
6x^2-17x-19=0