А)3(1+2xy)(1-2xy) б)(x^2-y^3)^2= в)(a+b)^2-(a-b)^2= №2 а)(4x-3)(4x+3)-(4x-1)^2=3x

Question

А)3(1+2xy)(1-2xy)
б)(x^2-y^3)^2=
в)(a+b)^2-(a-b)^2=
№2
а)(4x-3)(4x+3)-(4x-1)^2=3x

Answer 1

А) 3+6xy(1-2xy)=3+6xy-12xy=3-6xy
б) x^4-y^6
в) a^2+b^2-a^2-b^2=0

а) 4x-3*4x+3-8x+2=3x
    4x+4x-8x-3x=-3-2+3
    -3x=-2
    x=-2/3