Плиз,очень надо,сама не понимаю не чего:с

Question 1

Question 2

1-4.
9х²+3х = 3х (3х+1)
2аb - ab²= ab (2-b)
6xy +3x²y-12xy²= 3xy(2+х-4у)=3ху(х-4у+2)
5а⁴-10а³+10а²= 5а²(а²-2а+2)

5-8.
у(у-1) +2(у-1) = (у-1)(у+2)
ах-ау +2х-2у= а(х-у) +2(х-у) = (х-у)(а+2)
х²-64 = х²-8²= (х-8)(х+8)
9а²- 16b²= (3a)² - (4b)²= (3a-4b)(3a+4b)

9-12.
$\frac{ x^{2} +3x}{3a+ax} = \frac{x(x+3)}{a(x+3)} = \frac{x}{a} \\ \\$

$\frac{b^2}{b^2+bc} = \frac{b*b}{b(b+c)} = \frac{b}{b+c} \\ \\$

$\frac{2a+4}{a^2-4} = \frac{2(a+2)}{(a-2)(a+2) } = \frac{2}{a-2}$

$\frac{x^2-y^2}{x^2-xy} = \frac{(x-y)(x+y)}{x(x-y)} = \frac{x+y}{x}$

13-16.
(x-a)(x+a)=x²-a²
(2p-3n)(2p+3n)= (2p)²-(3n)²=4p²-9n²

(a+b)²-(a-b)(a+b) = a²-2ab+b²- (a²-b²) = a²-2ab+b²-a²+b²=
=2b²-2ab= 2b(b-a)

(x-1)(x+1)- x(x-3) = x²-1²-x²+3x= 3x-1

Question 3

1)3х(3х+1)
2)аb(2-b)
3)3xy(2+x+4y)
4)5a²(a²-2a+2)
5)(y+2)*(y-1)
6)a(x-y)+2(x-y)=(a+2)*(x-y)
7)(x-8)*(x+8)
8)(3a-4b)*(3a+4b)
9)x(x+3) / a(x+3)=x/a
10)b² / b(b+c)=b / b+c
11)2(a+2) / (a-2)(a+2)=2 / a-2
12)(x+y)(x-y) / x(x-y)= x+y / x

zhenyaM2002_zn · Answer 1 · 2018-04-20T07:35:41+0000

1-4.
9х²+3х = 3х (3х+1)
2аb - ab²= ab (2-b)
6xy +3x²y-12xy²= 3xy(2+х-4у)=3ху(х-4у+2)
5а⁴-10а³+10а²= 5а²(а²-2а+2)

5-8.
у(у-1) +2(у-1) = (у-1)(у+2)
ах-ау +2х-2у= а(х-у) +2(х-у) = (х-у)(а+2)
х²-64 = х²-8²= (х-8)(х+8)
9а²- 16b²= (3a)² - (4b)²= (3a-4b)(3a+4b)

9-12.
$\frac{ x^{2} +3x}{3a+ax} = \frac{x(x+3)}{a(x+3)} = \frac{x}{a} \\ \\$

$\frac{b^2}{b^2+bc} = \frac{b*b}{b(b+c)} = \frac{b}{b+c} \\ \\$

$\frac{2a+4}{a^2-4} = \frac{2(a+2)}{(a-2)(a+2) } = \frac{2}{a-2}$

$\frac{x^2-y^2}{x^2-xy} = \frac{(x-y)(x+y)}{x(x-y)} = \frac{x+y}{x}$

13-16.
(x-a)(x+a)=x²-a²
(2p-3n)(2p+3n)= (2p)²-(3n)²=4p²-9n²

(a+b)²-(a-b)(a+b) = a²-2ab+b²- (a²-b²) = a²-2ab+b²-a²+b²=
=2b²-2ab= 2b(b-a)

(x-1)(x+1)- x(x-3) = x²-1²-x²+3x= 3x-1