1) 4х^2-х-12=0 2) (3х+1)(2х^2+х-3)=0 3) 2х^2-4х-14=0

Question

1) 4х^2-х-12=0
2) (3х+1)(2х^2+х-3)=0
3) 2х^2-4х-14=0

Answer 1

4х²-х-12=0
D=1+48=49=7²
х₁=(1+7)/8=1
х₂=(1-7)/8=-6/8=-3/4=-0,75

(3х+1)(2х²+х-3)=0
3х₁+1=0      х₁=-1/3
2х²+х-3=0
D=1+24=25=5²
х₂=(-1+5)/4=1
х₃=(-1-5)/4=-6/4=-1,5

2х²-4х-14=0
х²-2х-7=0
D=4+28=32=(4√2)²
х₁=(2+4√2)/2=1+2√2
х₂=(2-4√2)/2=1-2√2