(sin 752 + cos 328) / √2 * sin 437

Question

(sin 752 + cos 328) / √2 * sin 437

Answer 1

(sin(720+32)+cos(270+58))/√2*sin(360+77)=
=(sin32+sin58)/√2*sin77=2sin45cos13/√2*sin(90-13)=
=2*√2/2cos13:(√2cos13)==1