Решите!
[(1+cos2a)²/4+(1-cos2a)²/4]:(2-sin²2a)= 1/4*(1+2cos2a+cos²2a+1-2cos2a+cos²2a)*1/(2-sin²2a)= =1/4*(2+2cos²2a)*1/(2-sin²2a)=1/2*(1+cos²2a)*1/(2-sin²2a)= =1/2*(1+1-sin²2a)*1/(2-sin²2a)=1/2*(2-sin²2a)*1/(2-sin²2a)=1/2