упростите выражение (3 6х 1 ) 8х-13 __+ ______ - ___ :_____ х+4 х²+х-12 х-3 х²-16

$(\frac{3}{x+4}+\frac{6x}{x^2+x-12}-\frac{1}{x-3}):\frac{8x-13}{x^2-16}=$

$\frac{3(x-3)+6x-(x+4)}{(x+4)(x-3)}*\frac{(x-4)(x+4)}{8x-13}=\frac{3x-9+6x-x-4)}{x-3}*\frac{x-4}{8x-13}=$

$\frac{8x-13}{x-3}*\frac{x-4}{8x-13}=\frac{x-4}{x+3}$

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