F ( x ) = 2x^3-3x^2+6 f' (-3); f' (3)

Question

F ( x ) = 2x^3-3x^2+6 f' (-3); f' (3)

Answer 1

F(x)=-+6x

Comments

Спасибо :)

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f'(x)=x-2x/3+6

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f'(-3)= -3+2+6=5

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f'(3)= 3-2+6=7