Log3(2х-1)+log3(5-х)=2

Question

Log3(2х-1)+log3(5-х)=2

Answer 1

Log3(2x-1)+log3(5-x)=2
log3((2x-1)(5-x)=2
10x-2x²-5+x=3²=9
10x-2x²-5+x-9=0
-2x²+11x-14=0
D=121-4*(-2)*(-14)=9
x1=(-11+3)/(-4)=2
x2=(-11-3)/(-4)=3.5