помогите ∫(6:2)dx/√ 3x -2

Question

помогите ∫(6:2)dx/√ 3x -2

Answer 1

∫dx/√(3x-2) [2;6] = 1/3 * 2√(3x-2) [2;6] = 2/3*√(3x-2) [2;6] = F(6)-F(2) = 2/3*√(18-2) - 2/3*√(6-2) = 2/3*4-2/3*2 = 8/3-4/3=4/3