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Решите задачу:

$a) \frac{1.2*3.3}{4.4} = \frac{1.2*33}{44} =1.2*3:4=0.9. \\\\ b) \frac{19.8*(-5.6)}{6.3} =- \frac{198*5.6}{63} =- \frac{22*9*5.6}{7*9} =- \frac{22*56}{70} =-22*8:10=-17.6.\\\\c)9.1:7+2 \frac{5}{6} =1.3+ \frac{17}{6} = \frac{7.8}{6}+ \frac{17}{6} = \frac{248}{60} = \frac{62}{15}=4 \frac{2}{15} .\\\\d)(1.08- \frac{2}{25} ): \frac{5}{9} =(108/100 - 8/100):5/9=1:5/9= \frac{9}{5} .$