ПОМОГИТЕ СРОЧНОО 1. 12-(4-х)^2=х(3-х) 2. c^2+4bc+4b^2= 3. 100a^4-1/9b^2

Question

ПОМОГИТЕ СРОЧНОО
1. 12-(4-х)^2=х(3-х)
2. c^2+4bc+4b^2=
3. 100a^4-1/9b^2

Answer 1

1) 12-16+8х-х^2=3х-х^2
5х=4
х=4/5=0.8
2) =(с+2в)^2
3) (10а^2-в/3)(10а^2+в/3)

Answer 2

1. 12 -16 +8x -x² =3x -x²
-4 +8x -x² +x² -3x =0
5x =4
x =4/5
x=0.8

2. c² +4bc +4b² =(c +2b)² =(c +2b)(c +2b)

3. 100a^4 -1/9b² =(10a² -1/3b²)(10a² +1/3b²)