5/6b-5/9b+1=1/2b+1/3 Решить уравнение

$\frac{5}{6} b- \frac{5}{9} b+1= \frac{1}{2} b+ \frac{1}{3}$
$\frac{5}{6}b- \frac{5}{9}b-\frac{1}{2}b= \frac{1}{3}-1$
$\frac{15-10-9}{18} *b=- \frac{2}{3}$
$- \frac{2}{9} b=- \frac{2}{3}$
$b=- \frac{2}{3}:(- \frac{2}{9})$
$b=- \frac{2}{3}*- \frac{9}{2}= \frac{2*9}{3*2}$
$b=3$

$\frac{5}{6}*3- \frac{5}{9}*3+1= \frac{1}{2}*3+ \frac{1}{3}$

$\frac{15}{6}- \frac{15}{9}+1= \frac{3}{2}+ \frac{1}{3}$

$1 \frac{5}{6}=1 \frac{5}{6}$