X^3+4x^2-4x-16=0 Решите уравнение

Question

X^3+4x^2-4x-16=0
Решите уравнение

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Answer 1

X^2( x + 4) - 4( x + 4) = 0
( x + 4)( x^2 - 4) = 0
( x + 4)(x - 2)(x+ 2) =0
x + 4 = 0
x = - 4
x - 2 = 0
x = 2
x + 2 = 0
x = - 2
Ответ: x1 = - 4, x2 = 2, x3= - 2.