Решите неравенство (2x^2 - 8x)/(x - 7) <= x

Question

Решите неравенство (2x^2 - 8x)/(x - 7) <= x

Answer 1

(2x²-8x)/(x-7)≤x
(2x²-8x-x²+7x)/(x-7)≤0
f(x) =(x²-x)/(x-7)
ОДЗ:х-7≠0⇒х≠7
x²-x=0⇒x(x-1)=0⇒x=0;x=1
f(x)≤0; x∈(-∞;0]∪[1;7)