Решите систему уравнений: x²-y²=12 и x-y=2

Question

Решите систему уравнений: x²-y²=12 и x-y=2

Answer 1

X^2-y^2 = (x-y)(x+y) = 12
x-y = 2

2(x+y) = 12
x-y = 2

x+y = 6
x-y = 2

2x = 8
x-y = 2

x = 4
y = 2