Решите уравнение (cos2x-1)*корень(9-х^2)=0
Cos(2x-1)*корень(9-x^2) = 0 cos2x-1=0 9-x^2>=0 2x=1 -x^2>=-9 2x=2pi*n n∈Z x^2<=9<br>x=Pi*n x∈[-3;3]