1
7/(x+1)+(x+4)/2(x-1)=(3x²-38)/(x-1)(x+1)
x≠-1 U x≠1
14*(x-1)+(x+4)(x+1)=2(3x²-38)
6x²-76-14x+14-x²-x-4x-x-4=0
5x²-19x-66=0
D=361+1320=1681
x1=(19-41)/10=-2,2
x2=(19+41)/10=6
2
(2x-5)/x(x-3)+(x+2)/x(x+3)+(x-5)/(x-3)(x+3)=0
x≠3 x≠-3
(x+3)(2x-5)+(x+2)(x-3)+x(x-5)=0
2x²-5x+6x-15+x²-3x+2x-6+x²-5x=0
4x²-5x-21=0
D=25+336=361
x1=(5-19)/8=-7/4
x2=(5+19)/8=3 не удов усл